Torsion of a Circular Shaft
Inputs
N·m
m
Result
6.366e+7Pa
J = πd⁴/32; τ = T·r/J
τ = 100.00 × 0.010000 / 1.571e-8 = 6.366e+7 Pa
- Polar moment of area J: 1.571e-8 m⁴
- Max shear stress τ: 6.366e+7 Pa
Kernel 0.1.0 · Profile torsion-circular-shaft v0.1.0
J = πd⁴/32; τ = T·r/J
τ = 100.00 × 0.010000 / 1.571e-8 = 6.366e+7 Pa
Kernel 0.1.0 · Profile torsion-circular-shaft v0.1.0